For which of the following metal ions would there be no distinction between low spin and high spin in octahedral complexes?

Question

Quizplus · Accepted Answer

Cu(II) has a d9 electron configuration, which means it has one electron in the dx2-y2 orbital and four electrons in the dxy, dyz, and dxz orbitals. This means that regardless of whether it is in a low spin or high spin octahedral complex, the same four orbitals will be occupied and the same one will be unoccupied. Therefore, there will be no distinction between low spin and high spin complexes for Cu(II) in octahedral geometry.

For Which of the Following Metal Ions Would There Be