What is the mole percent of ethanol (C₂H₅OH) in the 180 proof vodka, which consists of 71.0 g of ethanol for every 10.0 g of water present?

Name: What is the mole percent of ethanol (C 2 H 5 OH) in the 180 proof vodka, which consists of 71.0 g of ethanol for every 10.0 g of water present?
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The Answer of What is the mole percent of ethanol (C₂H₅OH) in the 180 proof vodka, which consists of 71.0 g of ethanol for every 10.0 g of water present?

What Is the Mole Percent of Ethanol (C2H5OH) in the 180

What Is the Mole Percent of Ethanol (C₂H₅OH) in the 180