Tabulated below are initial rate data for the reaction 2Fe(CN)₆³^- + 2I^- $\rightarrow$2Fe(CN)₆⁴^- + I₂ What is the value of k?

Question

Quizplus · Accepted Answer

The rate law for the given reaction can be expressed as rate = k[I-][Fe(CN)6]4-. Comparing this form to the given initial rate data, it can be seen that the rate doubles when the concentration of [Fe(CN)6]4- is doubled. This indicates that the reaction is second order with respect to [Fe(CN)6]4-, and hence the rate constant k can be calculated by using the formula k = (rate)/( [I-][Fe(CN)6]4- ) = (10*2)/(10*10) = 0.2 M-1 s-1. Therefore, the best choice is C.

Tabulated Below Are Initial Rate Data for the Reaction 2Fe(CN)63- →\rightarrow→

Tabulated Below Are Initial Rate Data for the Reaction 2Fe(CN)₆³^- $\rightarrow$