The following initial rate data were found for the reaction
2MnO 4 - + 5H 2 C 2 O 4 + 6H + $\rightarrow$ 2Mn 2+ + 10CO 2 + 8H 2 O
-What is the value of the rate constant?

Question

The following initial rate data were found for the reaction
2MnO 4 - + 5H 2 C 2 O 4 + 6H + $\rightarrow$ 2Mn 2+ + 10CO 2 + 8H 2 O 
-What is the value of the rate constant?

Quizplus · Accepted Answer

The rate law for the reaction is given by:
rate = k [MnOS1U1B14S1U1B0S1U1P1-S1S1P0]^2 [HS1U1B12S1U1B0C]^5 [HS1U1B12S1U1B0O]^6
Comparing this with the general rate law: rate = k [A]^m [B]^n [C]^p, we get:
m = 2, n = 5, p = 6
Therefore, the overall order of the reaction is given by:
m + n + p = 2 + 5 + 6 = 13
The units of the rate constant k can be calculated as follows:
units of rate = M/s
units of [MnOS1U1B14S1U1B0S1U1P1-S1S1P0]^2 = M^2
units of [HS1U1B12S1U1B0C]^5 = M^5
units of [HS1U1B12S1U1B0O]^6 = M^6
substituting these values in the rate law equation and simplifying, we get:
k = (rate) / [MnOS1U1B14S1U1B0S1U1P1-S1S1P0]^2 [HS1U1B12S1U1B0C]^5 [HS1U1B12S1U1B0O]^6
Substituting the values from the given initial rate data, we get:
k = (2 F1F1F1S1F1F1F10) / (10S1U1P15 S1S1P0M • sS1U1P1-S1S1P0S1U1P12S1S1P0 [S1S1P0]^2 [S1U1P1-S1S1P0]^5 [S1U1P1-S1S1P0]^6
Simplifying further, we get:
k = (2 F1F1F1S1F1F1F10) / (10S1U1P15 S1S1P0MS1U1P1-S1S1P0S1U1P12S1S1P0 [S1U1P1-S1S1P0]^11)
which can be written as:
k = (2 F1F1F1S1F1F1F10) / (10S1U1P15 S1S1P0MS1U1P1-S1S1P0S1U1P12S1S1P0 [S1U1P1-S1S1P0]^5 [S1S1P0]^6)
Therefore, the correct answer is B.

The Following Initial Rate Data Were Found for the Reaction →\rightarrow→

The Following Initial Rate Data Were Found for the Reaction $\rightarrow$