The reaction
2NOBr $\rightarrow$ 2NO + Br 2
exhibits the rate law
Rate = k[NOBr] 2 where k = 1.0 *10 - 5 M - 1 • s - 1 at 25° C. This reaction is run where the initial concentration of NOBr ([NOBr] 0 ) is 1.00 * 10 - 1 M.
-The [NO] after 1.00 h has passed is

Question

The reaction
2NOBr $\rightarrow$ 2NO + Br 2 
exhibits the rate law
Rate = k[NOBr] 2  where k = 1.0 *10 - 5 M - 1 • s - 1 at 25° C. This reaction is run where the initial concentration of NOBr ([NOBr] 0 ) is 1.00 * 10 - 1 M.
-The [NO] after 1.00 h has passed is

Quizplus · Accepted Answer

The Answer of The reaction
2NOBr $\rightarrow$ 2NO + Br 2 
exhibits the rate law
Rate = k[NOBr] 2  where k = 1.0 *10 - 5 M - 1 • s - 1 at 25° C. This reaction is run where the initial concentration of NOBr ([NOBr] 0 ) is 1.00 * 10 - 1 M.
-The [NO] after 1.00 h has passed is

The Reaction 2NOBr →\rightarrow→ 2NO + Br2 Exhibits the Rate Law Rate = K[NOBr]2

The Reaction
2NOBr $\rightarrow$ 2NO + Br₂
Exhibits the Rate Law
Rate = K[NOBr]²