In 6 M HCl, the complex ion Ru(NH3) 63+ decomposes to a variety of products. The reaction is first order in Ru(NH3) 63+ and has a half-life of 14 h at 25°C. Under these conditions, how long will it take for the [Ru(NH3) 63+] to decrease to 53.0% of its initial value?
A) 6.6 h
B) 15 h
C) 5.6 h
D) 13 h
E) 7.4 h
Correct Answer:
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