A concentration cell is constructed using two Ni electrodes with Ni²⁺ concentrations of 1.70 M and 4.40 *10^-⁴ M in the two half-cells. The reduction potential of Ni²⁺ is -0.23 V. Calculate the potential of the cell at 25°C.

Question

Quizplus · Accepted Answer

The potential of a concentration cell can be calculated using the Nernst equation: E = E° - (RT/nF) * ln(Q). For a concentration cell, E° = 0, and Q = [Ni²⁺]_anode/[Ni²⁺]_cathode. Plugging in the values: E = 0 - (0.0592/2) * log(4.40 x 10⁻⁴ / 1.70) = +0.106 V.

A Concentration Cell Is Constructed Using Two Ni Electrodes with Ni2+

A Concentration Cell Is Constructed Using Two Ni Electrodes with Ni²⁺