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Given That Δ\Delta G°f for NH3 = -16

Question 117

Multiple Choice

Given that Δ\Delta G°f for NH3 = -16.67 kJ/mol, calculate the equilibrium constant for the following reaction at 298 K. N2(g) + 3H2(g) Given that \Delta G°<sub>f</sub> for NH<sub>3</sub> = -16.67 kJ/mol, calculate the equilibrium constant for the following reaction at 298 K. N<sub>2</sub>(g) + 3H<sub>2</sub>(g) 2NH<sub>3</sub>(g) A) 1.20 * 10<sup>-</sup><sup>3</sup> B) 6.98 * 10<sup>5</sup> C) 8.36 * 10<sup>-</sup><sup>2</sup> D) 8.36 * 10<sup>2</sup> E) 1.42 * 10<sup>-</sup><sup>6</sup> 2NH3(g)


A) 1.20 * 10-3
B) 6.98 * 105
C) 8.36 * 10-2
D) 8.36 * 102
E) 1.42 * 10-6

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