How many of the following compounds exhibit geometric isomers?
I.Pd(NH₃) ₂Br₂ (square planar)
II.[Co(H₂O) ₂]Br₃
III.[Ni(H₂O) ₄(NO₂) ₂]
IV.K₂[CoCl₄]

Question

How many of the following compounds exhibit geometric isomers? I.Pd(NH₃)₂Br₂ (square planar) II.[Co(H₂O)₂]Br₃ III.[Ni(H₂O)₄(NO₂)₂] IV.K₂[CoCl₄]

Quizplus · Accepted Answer

Geometric isomerism (cis-trans isomerism) occurs in compounds that have restricted rotation around a bond or within a ring structure, typically involving double bonds or coordination complexes. Compound I (Pd complex) is square planar and has different ligands in a way that allows for geometric isomerism. Compound II ([Co(H2O)4]Br2) and Compound IV (K[CoCl4]) do not allow for geometric isomerism due to their symmetrical arrangement of identical ligands. Compound III ([Ni(H2O)4(NO2)2]) can exhibit geometric isomerism due to the presence of different ligands (H2O and NO2) around the central metal in a coordination complex, allowing for cis and trans configurations. However, the question's formatting suggests a misinterpretation of the compounds' descriptions, leading to an incorrect analysis. Given the correct interpretation of the chemical formulas without the encoding errors, only the square planar Pd complex (I) clearly allows for geometric isomerism due to its coordination environment and the presence of different ligands, assuming the other compounds are described accurately based on the standard understanding of coordination chemistry and geometric isomerism.

How Many of the Following Compounds Exhibit Geometric Isomers