Which of the following crystal field diagrams is correct for Co(CN)₆^4-, where CN^- is a strong-field ligand? E) none of these

Question

Quizplus · Accepted Answer

Co(III) has six d-electrons, and CN- is a strong-field ligand that will pair up four of the electrons in a t2g set. ₆^4- is a tetradentate ligand donating four electrons, and ^- is a bidentate ligand donating two electrons. Therefore, Co(CN)₆^4- has a total of six electrons in the eg set. The crystal field splitting diagram for this gives a high-spin octahedral complex with a splitting pattern of t2g (lower) and eg (higher) energy levels. Choice B correctly shows this pattern with six electrons in the eg set.

Which of the Following Crystal Field Diagrams Is Correct for Co(CN)64-

Which of the Following Crystal Field Diagrams Is Correct for Co(CN)₆^4-