For the reaction 2N 2 O 5 (g) → 4NO 2 (g) + O 2 (g), the following data were collected. -The concentration N₂O₅ at 100 min will be approximately

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The rate law for the reaction is:Rate = k[N2O5]The integrated rate law is:ln[N2O5] = -kt + ln[N2O5]0where [N2O5]0 is the initial concentration of N2O5.We can use the integrated rate law to calculate the concentration of N2O5 at 100 min:ln[N2O5] = -k(100 min) + ln(0.10 × 10^-2 mol/L)ln[N2O5] = -6.91[N2O5] = 0.06 × 10^-2 mol/L

For the Reaction 2N2O5(g) → 4NO2(g) + O2(g), the Following

For the Reaction 2N₂O₅(g) → 4NO₂(g) + O₂(g), the Following