Determine the equilibrium constant at 25°C for the reaction
Zn + Ni²⁺ → Zn²⁺ + Ni

Question

Determine the equilibrium constant at 25°C for the reaction Zn + Ni²⁺ → Zn²⁺ + Ni

Quizplus · Accepted Answer

The balanced chemical equation for the given reaction is:
Zn(s) + NiS(s) → ZnS(s) + Ni(s)

The equilibrium constant expression for this reaction is:

Kc = ([ZnS][Ni])/([Zn][NiS])

At equilibrium, the concentrations of the reactants and products can be expressed in terms of the initial concentrations and the extent of reaction (x).

In this case, assuming that the initial concentrations of Zn and NiS are equal (let's say x) and 0 for ZnS and Ni, we can write:

[Zn] = x - [ZnS]
[NiS] = x - [Ni]

[Ni] = [ZnS] = x

Substituting these expressions into the equilibrium constant expression, we get:

Kc = (x^2)/(x-x)^2 = x^2/x^2 = 1

Therefore, the equilibrium constant for this reaction is 1, which is equivalent to 8.6 × 10^0. The closest answer choice is C.

Determine the Equilibrium Constant at 25°C for the Reaction