Substance X has a heat of vaporization of 55.4 kJ/mol at its normal boiling point (423°C) . For the process X(l) → X(g) at 1 atm and 423°C, calculate the value of:
-ΔS_surr

Question

Substance X has a heat of vaporization of 55.4 kJ/mol at its normal boiling point (423°C). For the process X(l) → X(g) at 1 atm and 423°C, calculate the value of: -ΔS_surr

Quizplus · Accepted Answer

The entropy change of the surroundings (ΔS_surr) is calculated using the formula ΔS_surr = -ΔH/T, where ΔH is the heat of vaporization and T is the temperature in Kelvin. Converting 423°C to Kelvin gives 696 K. Thus, ΔS_surr = -55,400 J/mol / 696 K = -79.6 J/K•mol.

Substance X Has a Heat of Vaporization of 55