When 0.157 mol of NH₃ is reacted with excess HCl, 6.91 kJ of energy is released as heat. What is ΔH for this reaction per mole of NH₃ consumed?

Question

Quizplus · Accepted Answer

The ΔH for the reaction per mole of NH₃ consumed can be calculated by dividing the total energy released by the number of moles reacted. Since 6.91 kJ of energy is released from 0.157 mol, ΔH = 6.91 kJ / 0.157 mol = 44.0 kJ/mol. The negative sign indicates that energy is released, making the correct answer -44.0 kJ.

When 0157 Mol of NH3 Is Reacted with Excess HCl, 6

When 0157 Mol of NH₃ Is Reacted with Excess HCl, 6