A 75.0-mL sample of 0.0500 M HCN (Ka = 6.2 × 10-10) is titrated with 0.500 M NaOH. What is [H+] in the solution after 3.0 mL of 0.500 M NaOH has been added?
A) 9.3 × 10-10 M
B) 5.2 × 10-13 M
C) 1.0 × 10-7 M
D) 4.1 × 10-10 M
E) none of these
Correct Answer:
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