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In the Reaction P4(g) 2P2(g)Kp = 0.500 Atm at 1052°C

Question 71

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In the reaction
P4(g)In the reaction P<sub>4</sub>(g)  2P<sub>2</sub>(g)K<sub>p</sub> = 0.500 atm at 1052°C.  In an experiment, P<sub>4</sub>(g) is initially placed into a container at 1052°C. The total pressure of the equilibrium mixture of P<sub>4</sub>(g) and P<sub>2</sub>(g) is 6.00 atm. Calculate the equilibrium pressures of P<sub>4</sub>(g) and P<sub>2</sub>(g). Calculate the fraction (by moles) of P<sub>4</sub>(g) that has dissociated to reach equilibrium. 2P2(g)Kp = 0.500 atm at 1052°C.
In an experiment, P4(g) is initially placed into a container at 1052°C. The total pressure of the equilibrium mixture of P4(g) and P2(g) is 6.00 atm. Calculate the equilibrium pressures of P4(g) and P2(g). Calculate the fraction (by moles) of P4(g) that has dissociated to reach equilibrium.

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Pressure of P4 = 4.50...

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