What volume of 5.00 M potassium hydroxide is required to prepare 46.6 mL of 0.285 M KOH?

Question

Quizplus · Accepted Answer

We can use the formula C1V1 = C2V2 where: 
C1 = 5.00 M (concentration of 5.00 M potassium hydroxide) 
V1 = volume of 5.00 M potassium hydroxide solution we want to find 
C2 = 0.285 M (concentration of the final solution) 
V2 = 46.6 mL (volume of the final solution)

Plugging in the values, we get:

5.00 M x V1 = 0.285 M x 46.6 mL

Solving for V1:

V1 = (0.285 M x 46.6 mL)/5.00 M

V1 = 2.66 mL

Therefore, the volume of 5.00 M potassium hydroxide required is 2.66 mL. Choice C is correct.

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