For the question(s) that follow, consider the following balanced equation.
Mg₃N₂(s) + 6H₂O(l) → 3Mg(OH)₂(s) + 2NH 3 (g)
-How many grams of H₂O are needed to produce 150 g of Mg(OH)₂?

Question

Quizplus · Accepted Answer

To find the grams of H₂O needed, first calculate the moles of Mg(OH)₂ produced: 150 g / 58.32 g/mol = 2.57 mol. According to the balanced equation, 6 moles of H₂O are needed for every 3 moles of Mg(OH)₂, so 2.57 mol Mg(OH)₂ requires 5.14 mol H₂O. The molar mass of H₂O is 18.02 g/mol, so 5.14 mol × 18.02 g/mol = 92.6 g, which rounds to 93 g.

For the Question(s) That Follow, Consider the Following Balanced Equation