The reaction for the combustion of heptane is C₇H₁₆ + 11O₂ → 7CO₂ + 8H₂O.
How many liters of CO₂ at STP are produced from the complete combustion of 2.00 moles of heptane?

Question

The reaction for the combustion of heptane is C₇H₁₆ + 11O₂ → 7CO₂ + 8H₂O. How many liters of CO₂ at STP are produced from the complete combustion of 2.00 moles of heptane?

Quizplus · Accepted Answer

At STP, 1 mole of gas occupies 22.4 L. The combustion of 1 mole of heptane produces 7 moles of CO₂. Therefore, 2 moles of heptane produce 14 moles of CO₂. Thus, the volume of CO₂ is 14 moles × 22.4 L/mole = 313.6 L, which rounds to 314 L.

The Reaction for the Combustion of Heptane Is C7H16

The Reaction for the Combustion of Heptane Is C₇H₁₆