25.0 mL of 0.212 M NaOH is neutralized by 13.6 mL of an HCl solution. The molarity of the NaOH solution is

Question

Quizplus · Accepted Answer

We can use the equation:

NaOH + HCl -> NaCl + H2O

To find the molarity of the NaOH solution, we need to use the equation:

M NaOH x V NaOH = M HCl x V HCl

where:

V NaOH = 25.0 mL 
M HCl = unknown 
V HCl = 13.6 mL

Substituting the values:

M NaOH x 25.0 mL = M HCl x 13.6 mL

M NaOH = (M HCl x 13.6 mL) / 25.0 mL

We can now solve for M NaOH by plugging in the given values:

M NaOH = (0.212 M x 13.6 mL) / 25.0 mL

M NaOH = 0.115 M

Therefore, the answer is D) 0.390 M.

250 ML of 0