How many milliliters of 0.200 M NaOH are required to completely neutralize 5.00 mL of 0.100 M H₃PO₄?

Question

Quizplus · Accepted Answer

H₃PO₄ is a triprotic acid, meaning it can donate three protons. The balanced equation for the neutralization is: H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂O. Therefore, 3 moles of NaOH are needed for every mole of H₃PO₄. The moles of H₃PO₄ are 5.00 mL * 0.100 M = 0.0005 moles. Thus, 0.0005 moles * 3 = 0.0015 moles of NaOH are needed. The volume of 0.200 M NaOH required is 0.0015 moles / 0.200 M = 0.0075 L = 7.50 mL.

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