0.50 mole of NaCl is added to 1.0 kg of water. The freezing point of the solution will be ________.
A)0.00 °C
B)0.93 °C
C)1.86 °C
D)-0.93 °C
E)-1.86 °C

Question

Quizplus · Accepted Answer

The freezing point depression can be calculated using the formula ΔTf = i * Kf * m, where i is the van't Hoff factor (2 for NaCl), Kf is the freezing point depression constant for water (1.86 °C kg/mol), and m is the molality (0.50 mol/kg). This gives ΔTf = 2 * 1.86 * 0.50 = 1.86 °C. The freezing point of the solution is 0 °C - 1.86 °C = -1.86 °C.

050 Mole of NaCl Is Added to 1