Zn(s) + 2HCl(aq) → H₂(g) + ZnCl₂(aq) When 25.0 g of Zn reacts, how many L of H₂ gas are formed at STP?

Name: Zn(s) + 2HCl(aq) → H 2 (g) + ZnCl₂(aq) When 25.0 g of Zn reacts, how many L of H 2 gas are formed at STP?
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Question

Quizplus · Accepted Answer

At STP, 1 mole of gas occupies 22.4 L. The molar mass of Zn is 65.38 g/mol, so 25.0 g of Zn is 0.382 mol. The reaction produces 0.382 mol of H₂, which is 0.382 mol × 22.4 L/mol = 8.56 L.

Zn(s) + 2HCl(aq) → H2(g) + ZnCl₂(aq) When 25

Zn(s) + 2HCl(aq) → H₂(g) + ZnCl₂(aq) When 25