In the reaction of silver nitrate with sodium chloride, how many grams of silver chloride will be produced from 100. g of silver nitrate when it is mixed with an excess of sodium chloride? The equation for the reaction is below. AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)

Question

Quizplus · Accepted Answer

The molar ratio of AgNO₃ to AgCl is 1:1, which means that 169.9 g of AgCl will be produced from 169.9 g of AgNO₃. However, we are given that we only have 100. g of AgNO₃. To find the amount of AgCl produced, we need to set up a proportion:

100 g AgNO₃ / (169.9 g AgNO₃/1 mol AgNO₃) = x g AgCl / (1 mol AgCl/143.32 g AgCl)

Simplifying the proportion yields:

x = (100 g AgNO₃)(1 mol AgCl/169.9 g AgNO₃)(143.32 g AgCl/1 mol AgCl) = 84.4 g AgCl

Therefore, the answer is C) 84.4 g of AgCl.

In the Reaction of Silver Nitrate with Sodium Chloride, How