Barium chloride and sodium sulfate react according to the following equation.
BaCl₂ + Na 2 SO₄ → BaSO₄ + 2NaCl
Answer the question(s) that follow about this reaction.
-How many grams of barium sulfate can be produced from 20.8 g of barium chloride?

Question

Quizplus · Accepted Answer

The molar mass of BaCl₂ is 208.23 g/mol, and the molar mass of BaSO₄ is 233.39 g/mol. From 20.8 g of BaCl₂, you have 0.1 mol (20.8 g / 208.23 g/mol). Since the reaction is 1:1, 0.1 mol of BaSO₄ is produced, which is 23.3 g (0.1 mol * 233.39 g/mol).

Barium Chloride and Sodium Sulfate React According to the Following