Barium chloride and sodium sulfate react according to the following equation.
BaCl₂ + Na 2 SO₄ → BaSO₄ + 2NaCl
Answer the question(s) that follow about this reaction.
-How many grams of barium chloride are needed to make 100. grams of barium sulfate?

Question

Quizplus · Accepted Answer

The molar mass of BaSO₄ is approximately 233.39 g/mol, and the molar mass of BaCl₂ is approximately 208.23 g/mol. To produce 100 g of BaSO₄, we need (100 g / 233.39 g/mol) = 0.428 mol of BaSO₄. Since the reaction is 1:1, we need 0.428 mol of BaCl₂, which is 0.428 mol * 208.23 g/mol = 89.2 g of BaCl₂.

Barium Chloride and Sodium Sulfate React According to the Following