The reaction for the combustion of heptane is C7H16 + 11O2 → 7CO2 + 8H2O. How many liters of CO2 at STP are produced from the complete combustion of 2.00 moles of heptane?

Question

Quizplus · Accepted Answer

At STP, 1 mole of any gas occupies 22.4 liters. The balanced equation shows that 1 mole of heptane produces 7 moles of CO2. Therefore, 2 moles of heptane produce 14 moles of CO2. Thus, 14 moles of CO2 will occupy 14 x 22.4 L = 313.6 L, which rounds to 314 L.

The Reaction for the Combustion of Heptane Is C7H16