An electron in an atom initially has an energy 5.5 eV above the ground state energy. It drops to a state with energy 3.2 eV above the ground state energy and emits a photon in the process. The wave associated with the photon has a wavelength of: A) 5.4 *10 ^- ⁷ m B) 3.0 *10 ^- ⁷ m C) 1.7 *^- ⁷m D) 1.15 * 10 ^- ⁷ m E) 1.0 *10 ^- ⁷m

Question

Quizplus · Accepted Answer

The energy of the photon is equal to the difference in energy between the two states, which is 5.5 eV - 3.2 eV = 2.3 eV. The wavelength of the photon is given by the equation:λ = hc/Ewhere h is Planck's constant, c is the speed of light, and E is the energy of the photon. Substituting the values into the equation, we get:λ = (6.626 x 10^-34 J s)(3 x 10^8 m/s) / (2.3 eV * 1.6 x 10^-19 J/eV) = 5.4 x 10^-7 mTherefore, the correct answer is A.

An Electron in an Atom Initially Has an Energy 5