A diffraction grating of width W produces a deviation $\lambda$in second order for light of wavelength $\lambda$. The total number N of slits in the grating is given by:
A) 2W$\lambda$/sin$\theta$
B) (W/$\lambda$)sin$\theta$
C) $\lambda$W/2sin$\theta$
D) (W/2$\lambda$)sin$\theta$
E) 2$\lambda$/sin$\theta$

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The Answer of A diffraction grating of width W produces a deviation $\lambda$in second order for light of wavelength $\lambda$. The total number N of slits in the grating is given by:
A) 2W$\lambda$/sin$\theta$
B) (W/$\lambda$)sin$\theta$
C) $\lambda$W/2sin$\theta$
D) (W/2$\lambda$)sin$\theta$
E) 2$\lambda$/sin$\theta$

A Diffraction Grating of Width W Produces a Deviation λ\lambdaλ In Second Order for Light of Wavelength

A Diffraction Grating of Width W Produces a Deviation $\lambda$ In Second Order for Light of Wavelength