The angular frequency of a certain RLC series circuit is $ \omega $₀. A source of sinusoidal emf, with angular frequency 2 $ \omega $, is inserted into the circuit. After transients die out the angular frequency of the current oscillations is: A) $ \omega $₀/2 B) $ \omega $₀ C) 2 $ \omega $₀ D) 1.5 $ \omega $₀ E) 3 $ \omega $₀

Question

Quizplus · Accepted Answer

The angular frequency of the current oscillations in an RLC circuit is equal to the resonance frequency, which is given by ω = 1/√(LC - R²/4L²). In this case, the given ω is equal to √(1/LC - R²/4L²), and the new source has ω = 2√(1/LC - R²/4L²). After transients die out, the circuit will oscillate at the new resonance frequency, which is ω' = √(1/LC - R²/4L²) * 2. Simplifying this expression gives ω' = 2√(1/LC - R²/4L²), which is equal to 2F1F1F1S1ωF1F1F10₀. Therefore, the answer is C.

The Angular Frequency of a Certain RLC Series Circuit Is ω \omega ω

The Angular Frequency of a Certain RLC Series Circuit Is $\omega$