Capacitor C₁ is connected alone to a battery and charged until the magnitude of the charge on each plate is 4.0 * 10^-⁸C. Then it is removed from the vattery and connected to two other capacitors C₂and C₃, as shown. The charge ont he positive placte of C₁ is then 1.0 * 10 ^- ⁸C. The charges on the positive plates of C₂ and C₃are: A) q₂ = 3.0 *10 ^- ^-8C and q₃ = 3.0 * 10 ^- ⁸C B) q₂ = 2.0 *10 ^- ⁸ Cand q₃ = 2.0 *10 ^- ⁸C C) q₂ = 5.0 *10 1^- ⁸ Cand q₃ = 1.0 *10 ^- ⁸C D) q₂ = 3.0 *10 ^- ⁸C and q₃ = 1.0 *10 ^- ⁸C E) q₂ = 1.0 * 10 ^- ⁸ Cand q₃ = 3.0 *10 ^- ⁸C

Question

Quizplus · Accepted Answer

According to conservation of charge, the total charge on the three capacitors must be equal to the initial charge on capacitor C₁, which is 4.0 F1F1F1S1F1F1F10 10F1F1F1S1^F1F1F10⁸C. Therefore, the sum of q₂ and q₃ must be 3.0 F1F1F1S1F1F1F10 10F1F1F1S1^F1F1F10^-8C (the remaining charge after 1.0 F1F1F1S1F1F1F10 10F1F1F1S1^F1F1F10⁸C is transferred to C₂ and C₃). Since the circuit is symmetrical, the charges on C₂ and C₃ must be equal, so each capacitor must have a charge of 3.0 F1F1F1S1F1F1F10 10F1F1F1S1^F1F1F10^-8C/2 = 1.5 F1F1F1S1F1F1F10 10F1F1F1S1^F1F1F10^{- 8}C. Therefore, the correct answer is A.

Capacitor C1 Is Connected Alone to a Battery and Charged

Capacitor C₁ Is Connected Alone to a Battery and Charged