A particle with charge 5.0-$\mu$C is placed at the corner of a cube. The total electric flux in N .m²/C through all sides of the cube is:

Question

Quizplus · Accepted Answer

The electric flux through a closed surface is given by the flux equation Φ = Q/ε0, where Q is the charge enclosed by the surface and ε0 is the permittivity of free space. In this case, the charge is located at a corner of the cube, so it is enclosed by all six sides of the cube. Hence, the total electric flux through all sides of the cube is Φ = Q/ε0 × 6. Plugging in the given values, we get: Φ = (5.0 × 10^-6 C) / (8.85 × 10^-12 N^-1 m^-2 C^2) × 6 = 3.39 × 10^6 N m^2 C^-1 Converting to nano-F1F1F1S1F1F1F10 10⁴/C, we get: Φ = 3.39 × 10^-3 N F1F1F1S1F1F1F10 10⁴/C ≈ 7.1 F1F1F1S1F1F1F10 10⁴/C Therefore, the best choice is B, as it is the closest approximation to the calculated value.

A Particle with Charge 5 μ\muμ C Is Placed at the Corner of a Cube

A Particle with Charge 5 $\mu$ C Is Placed at the Corner of a Cube