In the Rutherford model of the hydrogen atom, a proton (mass M, charge Q) is the nucleus and an electron (mass m, charge q) moves around the proton in a circle of radius r. Let k denote the Coulomb force constant (1/4 $\pi\(\varepsilon$₀) and G the universal gravitational constant. The ratio of the electrostatic force to the gravitational force between electron and proton is:

Question

Quizplus · Accepted Answer

The electrostatic force between the electron and the proton is given by Coulomb's law as kQq/r^2. 
The gravitational force between the electron and proton is given by the law of gravitation as G(Mm)/r^2. 
Taking the ratio of these two forces, we get (kQq/GMm), which is option E.

In the Rutherford Model of the Hydrogen Atom, a Proton π(ε\pi\\(\varepsilonπ(ε

In the Rutherford Model of the Hydrogen Atom, a Proton $\pi\\(\varepsilon$