A shearing force of 50 N is applied to an aluminum rod with a length of 10 m, a cross-sectional area of 1.0 *10-⁵ m, and shear modulus of 2.5 *10¹⁰N/m^2.As a result the rod is sheared through a distance of: A) zero B) 1.9 mm C) 1.9 cm D) 19 cm E) 1.9 m

Question

Quizplus · Accepted Answer

The shear strain is calculated using the formula: shear strain = shear force / (shear modulus × area). Substituting the given values, the shear strain is 50 N / (2.5 × 10^10 N/m² × 10^-5 m²) = 2 × 10^-4. The sheared distance is then shear strain × length = 2 × 10^-4 × 10 m = 0.002 m = 2 mm, which is approximately 1.9 mm.

A Shearing Force of 50 N Is Applied to an Aluminum