A 15-g paper clip is attached to the rim of a phonograph record with a radius of 30 cm, spinning at 3.5 rad/s. The magnitude of its angular momentum is: A) 1.4 * 10^-³ kg .m²/s B) 4.7* 10^-³ kg .m²/s C) 1.6 * 10^-^-2 kg.m²/s D) 3.2 * 10^-¹ kg . m²/s E) 1.1 kg . m²/s

Question

Quizplus · Accepted Answer

The angular momentum (L) of the paper clip can be calculated using the formula L = Iω, where I is the moment of inertia and ω is the angular velocity. For a point mass, the moment of inertia is equal to mr^2, where m is the mass and r is the radius. Plugging in the given values, we get:

I = (0.015 kg)(0.3 m)^2 = 0.00135 kg•m^2
ω = 3.5 rad/s
L = (0.00135 kg•m^2)(3.5 rad/s) = 0.0047 kg•m^2/s

Therefore, the magnitude of the angular momentum is 0.0047 kg•m^2/s, which corresponds to choice B.

A 15-G Paper Clip Is Attached to the Rim of a Phonograph