The potential energy of a particle moving along the x axis is given by U(x) = (8.0J/m²) x² + (2.0J/m4) x⁴.
If the total mechanical energy is 9.0 J, the limits of motion are:

Question

The potential energy of a particle moving along the x axis is given by U(x) = (8.0J/m²)x² + (2.0J/m4)x⁴. If the total mechanical energy is 9.0 J, the limits of motion are:

Quizplus · Accepted Answer

The limits of motion are found by setting the potential energy U(x) equal to the total mechanical energy (9.0 J) and solving for x. Solving the equation (8.0)x^2 + (2.0)x^4 = 9.0 gives x = ±0.96 m.

The Potential Energy of a Particle Moving Along the X