When a certain rubber band is stretched a distance x, it exerts a restoring force of magnitude F = Ax, where A is a constant. The work done by a person in stretching this rubber band from x = 0 to x = L is:

Question

Quizplus · Accepted Answer

The work done in stretching a spring is given by W = (1/2)kx^2, where k is the spring constant and x is the displacement from the equilibrium position. In this case, F = Ax, so the restoring force is proportional to the displacement, meaning that the rubber band behaves like a spring with spring constant k = A. Therefore, the work done in stretching the rubber band from x = 0 to x = L is: W = (1/2)k(L^2 - 0^2) W = (1/2)AL^2 Substituting the value of k, we get: W = (1/2)Ax^2 Hence, the correct answer is E: AL²/2

When a Certain Rubber Band Is Stretched a Distance X