The speed of a 4.0-N hockey puck, sliding across a level ice surface, decreases at the rate of 0.61 m/s². The coefficient of kinetic friction between the puck and ice is: A) 0.062 B) 0.41 C) 0.62 D) 1.2 E) 9.8

Question

Quizplus · Accepted Answer

The force of friction is equal to the mass times the acceleration (F = ma). The weight of the puck is 4.0 N, which is equal to the normal force (N). The frictional force is also equal to the coefficient of kinetic friction (μ) times the normal force (F_friction = μN). Therefore, μ = a/g = 0.61/9.8 = 0.062.

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