A short 10-g string is used to pull a 50-g toy across a frictionless horizontal surface. If a 3.0 * 10^-²-N force is applied horizontally to the free end, the force of the string on the toy, at the other end, is: A) 0.15 N B) 6.0 * 10^-³ N C) 2.5 * 10^-² N D) 3.0 * 10^-² N E) 3.5 *10^-² N

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Quizplus · Accepted Answer

The force applied to the system (string + toy) is 3.0 x 10^-2 N. The total mass of the system is 60 g (10 g string + 50 g toy), which is 0.06 kg. The acceleration of the system is F/m = (3.0 x 10^-2 N) / 0.06 kg = 0.5 m/s². The force on the toy is its mass times the acceleration: 0.05 kg * 0.5 m/s² = 2.5 x 10^-2 N.

A Short 10-G String Is Used to Pull a 50-G