A particle goes from x = -2 m, y = 3 m, z = 1 m to x = 3 m, y = -1 m, z = 4 m. Its displacement is:

Question

Quizplus · Accepted Answer

Using the distance formula, we get:
d = sqrt((3 - (-2))^2 + (-1 - 3)^2 + (4 - 1)^2) = sqrt(25 + 16 + 9) = sqrt(50) = 5sqrt(2)
Therefore, the displacement is 5sqrt(2) meters in magnitude and in the direction from (-2, 3, 1) to (3, -1, 4), which is represented by the vector (5, -4, 3). Choice B is the option that represents this vector in the given format.

A Particle Goes from X = -2 M, Y =