An object is released from rest.How far does it fall during the second second of its fall?
A)4.9 m
B)9.8 m
C)15 m
D)20 m
E)25 m

Question

Quizplus · Accepted Answer

The distance fallen during the second second can be calculated using the formula for distance fallen under gravity: $ s = ut + \frac{1}{2}gt^2 $. For the second second, calculate the distance fallen in 2 seconds and subtract the distance fallen in 1 second. This gives $ s_2 = \frac{1}{2}g(2^2) - \frac{1}{2}g(1^2) = 19.6 - 4.9 = 14.7 \approx 15 $ m.

An Object Is Released from Rest