A heavy ball falls freely, starting from rest. Between the third and fourth second of time it travels a distance of:
A) 4.9 m.
B) 9.8 m.
C) 29.4 m
D) 34.3 m.
E) 39.8 m.

Question

Quizplus · Accepted Answer

Assuming the ball is falling vertically under the influence of gravity, we can use the formula for displacement:

d = 1/2 * g * t^2

where d is the displacement, g is the acceleration due to gravity (9.8 m/s^2), and t is the time.

Between the third and fourth second, the time interval is 1 second. Plugging in the values:

d = 1/2 * 9.8 * (4^2 - 3^2) = 34.3 m

Therefore, the ball travels a distance of 34.3 meters between the third and fourth second.

A Heavy Ball Falls Freely, Starting from Rest