One object is thrown vertically upward with an initial velocity of 100 m/s and another object with an initial velocity of 10 m/s.The maximum height reached by the first object will be _______ that of the other.
A)10 times
B)100 times
C)1000 times
D)10,000 times
E)none of these

Question

Quizplus · Accepted Answer

The maximum height reached by an object thrown vertically upward is given by:
$h=\frac{v^2}{2g}$, where v is the initial velocity and g is the acceleration due to gravity (9.8 m/s^2).
For the first object: $h_1=\frac{(100)^2}{2(9.8)}=510.2$ m
For the second object: $h_2=\frac{(10)^2}{2(9.8)}=5.1$ m
Therefore, the maximum height reached by the first object is 100 times greater than that of the second object.

One Object Is Thrown Vertically Upward with an Initial Velocity