Pi mesons at rest have a half-life of T. If a beam of pi mesons is traveling at a speed of v = $\beta$c, the distance in which the intensity of the beam is halved is: A) c$\beta$T(1 - $\beta$²)^-^1/2 B) c$\beta$T[(1 + $\beta$)/(1 - $\beta$)]^1/2 C) $\beta$vT D) (1 - $\beta$²)^1/2vT E) none of the above

Question

Quizplus · Accepted Answer

The correct answer is A because the distance in which the intensity of the beam is halved is given by the formula cT(1 - v^2/c^2)^-1/2, where c is the speed of light, T is the half-life of the pi mesons, and v is the speed of the pi mesons.

Pi Mesons at Rest Have a Half-Life of T β\betaβ C, the Distance in Which the Intensity of the Beam

Pi Mesons at Rest Have a Half-Life of T $\beta$ C, the Distance in Which the Intensity of the Beam