An electron (m = 9.11 * 10^-³¹ kg) has a speed of 0.95c. Its kinetic energy is: A) 8.2 * 10^-¹⁴ J B) 1.8 * 10^-¹³ J C) 2.0 * 10^-¹³ J D) 2.2 * 10^-¹³ J E) 2.6 * 10^-¹³ J

Question

Quizplus · Accepted Answer

The relativistic kinetic energy is calculated using the formula $ KE = (\gamma - 1)mc^2 $, where $\gamma = \frac{1}{\sqrt{1 - v^2/c^2}} $. For $ v = 0.95c $, $\gamma \approx 3.202 $. Substituting the values, the kinetic energy is approximately $ 1.8 \times 10^{-13} $ J.

An Electron (M = 9