A beam of x rays of wavelength 0.10nm is found to diffract in second order from the face of a LiF crystal at a Bragg angle of 30$\degree$. The distance between adjacent crystal planes, in nm, is about:
A) 0.15
B) 0.20
C) 0.25
D) 0.30
E) 0.40

Question

Quizplus · Accepted Answer

We can use Bragg's Law to solve for the distance between adjacent crystal planes:

nλ = 2d sinθ

where n is the order of diffraction, λ is the wavelength of the x-ray beam, d is the distance between adjacent crystal planes, and θ is the Bragg angle.

In this case, n = 2, λ = 0.10 nm, and θ = 30°.

Solving for d, we get:

d = λ/(2sinθ/n)

d = 0.10 nm / (2 sin 30° / 2)

d = 0.20 nm

Therefore, the answer is (B) 0.20 nm.

A Beam of X Rays of Wavelength 0 °\degree° the Distance Between Adjacent Crystal Planes, in Nm, Is

A Beam of X Rays of Wavelength 0 $\degree$ the Distance Between Adjacent Crystal Planes, in Nm, Is