Light with an intensity of 1 kW/m² falls normally on a surface with an area of 1 cm² and is completely absorbed. The force of the radiation on the surface is: A) 1.0 * 10^-⁴ N B) 3.3 * 10^-¹¹ N C) 1.7 * 10^-¹⁰ N D) 3.3 * 10^-¹⁰ N E) 6.7 *10^-¹⁰ N

Question

Quizplus · Accepted Answer

The force of radiation is given by the equation F = P/c, where P is the power of the radiation and c is the speed of light. In this case, the power is 1 kW/m^2 and the area is 1 cm^2, so the force is:F = (1 kW/m^2) * (1 cm^2) / (3 x 10^8 m/s) = 3.3 x 10^-10 N

Light with an Intensity of 1 KW/m2 Falls Normally on a Surface

Light with an Intensity of 1 KW/m² Falls Normally on a Surface