As a loop of wire with a resistance of 10 $\Omega$ moves in a non-uniform magnetic field, it loses kinetic energy at a uniform rate of 5 mJ/s. The induced emf in the loop:
A) is 0
B) is 0.2 V
C) is 0.28 V
D) is 2 V
E) cannot be calculated from the given data

Question

As a loop of wire with a resistance of 10  $\Omega$ moves in a non-uniform magnetic field, it loses kinetic energy at a uniform rate of 5 mJ/s. The induced emf in the loop:
A) is 0
B) is 0.2 V
C) is 0.28 V
D) is 2 V
E) cannot be calculated from the given data

Quizplus · Accepted Answer

The power loss due to resistance is given by P = I^2 * R. Given P = 5 mJ/s and R = 10 Ω, we can find I = sqrt(P/R) = sqrt(0.005/10) = 0.02236 A. The induced emf (E) is given by E = I * R = 0.02236 * 10 = 0.2236 V, which rounds to 0.2 V.

As a Loop of Wire with a Resistance of 10 Ω\OmegaΩ

As a Loop of Wire with a Resistance of 10 $\Omega$