You are facing a loop of wire which carries a clockwise current of 3.0 A and which surrounds an area of 5.8 10⁻²m². The magnetic dipole moment of the loop is: A) 3.0 A. m², into the page B) 3.0 A . m², out of the page C) 0.17 A .m², into the page D) 0.17 A . m², out of the page E) 0.17 A .m², left to right

Question

Quizplus · Accepted Answer

The magnetic dipole moment can be calculated using the formula:
Magnetic dipole moment (m) = current (I) x area (A) x unit vector perpendicular to the plane of the loop.

In this case, the current is clockwise, which means the magnetic field produced by it will be into the page. The unit vector perpendicular to the plane of the loop will also be into the page. So, the magnetic dipole moment will be:
m = 3.0 A x 5.8x10^-4 m^2 x (-k) (where k is the unit vector perpendicular to the plane of the loop, pointing into the page)
m = -0.00174 A m^2 k

Neglecting the negative sign and converting to proper units, we get:
m = 0.17 A m^2 k
So, the answer is (C).

You Are Facing a Loop of Wire Which Carries a Clockwise