Four 20-$\Omega$ resistors are connected in series and the combination is connected to a 20-V emf device.The current in any one of the resistors is:
A)0.25 A
B)1.0 A
C)4.0 A
D)5.0 A
E)100 A

Question

Quizplus · Accepted Answer

When four 20-ohm resistors are connected in series, their total resistance is the sum of their individual resistances, which is 20 + 20 + 20 + 20 = 80 ohms. Using Ohm's law (V = IR), where V is the voltage (20 V) and R is the total resistance (80 ohms), the current (I) can be calculated as I = V/R = 20/80 = 0.25 A.

Four 20- Ω\OmegaΩ Resistors Are Connected in Series and the Combination Is Connected

Four 20- $\Omega$ Resistors Are Connected in Series and the Combination Is Connected